If a circuit is supplied with a 480-volt, 60-hertz source and has a capacitive reactance of 30 ohms, what is the maximum current flow?

To determine the maximum current flow in a circuit supplied with a voltage of 480 volts and having a capacitive reactance of 30 ohms, one can apply Ohm’s Law in the context of AC circuits involving reactance.

In an AC circuit, the relationship between voltage (V), current (I), and reactance (X) is expressed by the formula:

[ I = \frac{V}{X} ]

Here, V is the voltage (480 volts) and X is the capacitive reactance (30 ohms).

By substituting the given values into the formula:

[ I = \frac{480 , \text{volts}}{30 , \text{ohms}} ]

Calculating this gives:

[ I = 16 , \text{A} ]

This shows that the maximum current flow through the circuit is 16 amperes.

In this problem, it's essential to focus on how reactance affects the current. Capacitive reactance reduces the current flow in response to the applied voltage, and the maximum current is determined using this formula, ensuring that proper units are utilized. Therefore, the correct answer reflects this calculation and application of circuit theory.